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答案：
B
问有小数点
后多少个0，则要凑10负几次方。可以先将t的分母写成(2*5)^3*2^6，即提出3个2*5=10来，10^(-3)，除以10^3，小数点向前移动3位，会新产生3个0，这样看1/64小数后面有几个0，再加上3即可。
2^9*5^3 = (2*5)^3*2^6 = 10^(-3)*(1/64)
1/64=1.00/64，很显然要要补出2个0成100才能商1，即到百分位商1。因此1/64小数点后和第一个非零数字之间有1个0，加上前面的10^(-3)中的3个共4个0，即t小数点到第一个非0数字之间有4个0，选B。 
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